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def spellingNormalization (sWord):
"nomalization NFC and removing ligatures"
return unicodedata.normalize("NFC", sWord.translate(_xTransCharsForSpelling))
_xTransCharsForSimplification = str.maketrans({
'à': 'a', 'é': 'e', 'î': 'i', 'ô': 'o', 'û': 'u', 'ÿ': 'i', "y": "i",
'â': 'a', 'è': 'e', 'ï': 'i', 'ö': 'o', 'ù': 'u', 'ŷ': 'i',
'ä': 'a', 'ê': 'e', 'í': 'i', 'ó': 'o', 'ü': 'u', 'ý': 'i',
'á': 'a', 'ë': 'e', 'ì': 'i', 'ò': 'o', 'ú': 'u', 'ỳ': 'i',
'ā': 'a', 'ē': 'e', 'ī': 'i', 'ō': 'o', 'ū': 'u', 'ȳ': 'i',
'ç': 'c', 'ñ': 'n', 'k': 'q', 'w': 'v',
'œ': 'oe', 'æ': 'ae',
'ſ': 's', 'ffi': 'ffi', 'ffl': 'ffl', 'ff': 'ff', 'ſt': 'ft', 'fi': 'fi', 'fl': 'fl', 'st': 'st',
})
def simplifyWord (sWord):
"word simplication before calculating distance between words"
sWord = sWord.lower().translate(_xTransCharsForSimplification)
sNewWord = ""
for i, c in enumerate(sWord, 1):
if c == 'e' or c != sWord[i:i+1]: # exception for <e> to avoid confusion between crée / créai
sNewWord += c
return sNewWord.replace("eau", "o").replace("au", "o").replace("ai", "e").replace("ei", "e").replace("ph", "f")
aVowel = set("aáàâäāeéèêëēiíìîïīoóòôöōuúùûüūyýỳŷÿȳœæAÁÀÂÄĀEÉÈÊËĒIÍÌÎÏĪOÓÒÔÖŌUÚÙÛÜŪYÝỲŶŸȲŒÆ")
aConsonant = set("bcçdfghjklmnñpqrstvwxzBCÇDFGHJKLMNÑPQRSTVWXZ")
aDouble = set("bcdfjklmnprstzBCDFJKLMNPRSTZ") # letters that may be used twice successively
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def spellingNormalization (sWord):
"nomalization NFC and removing ligatures"
return unicodedata.normalize("NFC", sWord.translate(_xTransCharsForSpelling))
_xTransCharsForSimplification = str.maketrans({
'à': 'a', 'é': 'é', 'î': 'i', 'ô': 'o', 'û': 'u', 'ÿ': 'i', "y": "i",
'â': 'a', 'è': 'é', 'ï': 'i', 'ö': 'o', 'ù': 'u', 'ŷ': 'i',
'ä': 'a', 'ê': 'é', 'í': 'i', 'ó': 'o', 'ü': 'u', 'ý': 'i',
'á': 'a', 'ë': 'é', 'ì': 'i', 'ò': 'o', 'ú': 'u', 'ỳ': 'i',
'ā': 'a', 'ē': 'é', 'ī': 'i', 'ō': 'o', 'ū': 'u', 'ȳ': 'i',
'ç': 'c', 'ñ': 'n', 'k': 'q', 'w': 'v',
'œ': 'oe', 'æ': 'ae',
'ſ': 's', 'ffi': 'ffi', 'ffl': 'ffl', 'ff': 'ff', 'ſt': 'ft', 'fi': 'fi', 'fl': 'fl', 'st': 'st',
})
def simplifyWord (sWord):
"word simplication before calculating distance between words"
sWord = sWord.lower().translate(_xTransCharsForSimplification)
sNewWord = ""
for i, c in enumerate(sWord, 1):
if c == 'e' or c != sWord[i:i+1]: # exception for <e> to avoid confusion between crée / créai
sNewWord += c
return sNewWord.replace("eau", "o").replace("au", "o").replace("ai", "ê").replace("ei", "ê").replace("ph", "f")
aVowel = set("aáàâäāeéèêëēiíìîïīoóòôöōuúùûüūyýỳŷÿȳœæAÁÀÂÄĀEÉÈÊËĒIÍÌÎÏĪOÓÒÔÖŌUÚÙÛÜŪYÝỲŶŸȲŒÆ")
aConsonant = set("bcçdfghjklmnñpqrstvwxzBCÇDFGHJKLMNÑPQRSTVWXZ")
aDouble = set("bcdfjklmnprstzBCDFJKLMNPRSTZ") # letters that may be used twice successively
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