Grammalecte  Diff

Differences From Artifact [e440be0f51]:

To Artifact [047ef79ee5]:


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//// STRING TRANSFORMATION
/*jslint esversion: 6*/




// Note: 48 is the ASCII code for "0"

var str_transform = {







































    distanceDamerauLevenshtein2: function (s1, s2) {
        // distance of Damerau-Levenshtein between <s1> and <s2>
        // https://fr.wikipedia.org/wiki/Distance_de_Damerau-Levenshtein
        try {
            let nLen1 = s1.length;
            let nLen2 = s2.length;



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//// STRING TRANSFORMATION
/*jslint esversion: 6*/

"use strict";


// Note: 48 is the ASCII code for "0"

var str_transform = {

    longestCommonSubstring: function (string1, string2) {
        // https://en.wikibooks.org/wiki/Algorithm_Implementation/Strings/Longest_common_substring
        // untested

        // init max value
        let longestCommonSubstring = 0;
        // init 2D array with 0
        let table = [],
            len1 = string1.length,
            len2 = string2.length,
            row, col;
        for (row = 0; row <= len1; row++) {
            table[row] = [];
            for (col = 0; col <= len2; col++) {
                table[row][col] = 0;
            }
        }
        // fill table
        let i, j;
        for (i = 0;  i < len1;  i++) {
            for (j = 0;  j < len2;  j++) {
                if (string1[i] === string2[j]) {
                    if (table[i][j] === 0){
                        table[i+1][j+1] = 1;
                    } else {
                        table[i+1][j+1] = table[i][j] + 1;
                    }
                    if (table[i+1][j+1] > longestCommonSubstring) {
                        longestCommonSubstring = table[i+1][j+1];
                    }
                } else {
                    table[i+1][j+1] = 0;
                }
            }
        }
        return longestCommonSubstring;
    },

    distanceDamerauLevenshtein2: function (s1, s2) {
        // distance of Damerau-Levenshtein between <s1> and <s2>
        // https://fr.wikipedia.org/wiki/Distance_de_Damerau-Levenshtein
        try {
            let nLen1 = s1.length;
            let nLen2 = s2.length;
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                break;
            }
            jSfx += 1;
        }
        return String.fromCharCode(sFlex.length-jSfx+48) + sStem.slice(jSfx);
    },

    getStemFromSuffixCode: function (sFlex, sSfxCode) {
        // Suffix only
        if (sSfxCode == "0") {
            return sFlex;
        }
        return sSfxCode[0] == '0' ? sFlex + sSfxCode.slice(1) : sFlex.slice(0, -(sSfxCode.charCodeAt(0)-48)) + sSfxCode.slice(1);
    },
    
    getStemFromAffixCode: function (sFlex, sAffCode) {
        // Prefix and suffix

































        if (sAffCode == "0") {
            return sFlex;
        }
        if (!sAffCode.includes("/")) {
            return "# error #";
        }
        let [sPfxCode, sSfxCode] = sAffCode.split('/');
        sFlex = sPfxCode.slice(1) + sFlex.slice(sPfxCode.charCodeAt(0)-48);
        return sSfxCode[0] == '0' ? sFlex + sSfxCode.slice(1) : sFlex.slice(0, -(sSfxCode.charCodeAt(0)-48)) + sSfxCode.slice(1);
    }
};


if (typeof(exports) !== 'undefined') {
    exports.getStemFromSuffixCode = str_transform.getStemFromSuffixCode;
    exports.getStemFromAffixCode = str_transform.getStemFromAffixCode;
}







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                break;
            }
            jSfx += 1;
        }
        return String.fromCharCode(sFlex.length-jSfx+48) + sStem.slice(jSfx);
    },

    changeWordWithSuffixCode: function (sWord, sSfxCode) {

        if (sSfxCode == "0") {
            return sWord;
        }
        return sSfxCode[0] == '0' ? sWord + sSfxCode.slice(1) : sWord.slice(0, -(sSfxCode.charCodeAt(0)-48)) + sSfxCode.slice(1);
    },
    

    // Prefix and suffix
    defineAffixCode: function (sFlex, sStem) {
        /*
            UNTESTED!
            Returns a string defining how to get stem from flexion. Examples:
                "0" if stem = flexion
                "stem" if no common substring
                "n(pfx)/m(sfx)"
            with n and m: chars with numeric meaning, "0" = 0, "1" = 1, ... ":" = 10, etc. (See ASCII table.) Says how many letters to strip from flexion.
                pfx [optional]: string to add before the flexion 
                sfx [optional]: string to add after the flexion
        */
        if (sFlex == sStem) {
            return "0";
        }
        // is stem a substring of flexion?
        let n = sFlex.indexOf(sStem);
        if (n >= 0) {
            return String.fromCharCode(n+48) + "/" + String.fromCharCode(sFlex.length-(sStem.length+n)+48);
        }
        // no, so we are looking for common substring
        let sSubs = this.longestCommonSubstring(sFlex, sStem);
        if (sSubs.length > 1) {
            let iPos = sStem.indexOf(sSubs);
            let sPfx = sStem.slice(0, iPos);
            let sSfx = sStem.slice(iPos+sSubs.length);
            let n = sFlex.indexOf(sSubs);
            let m = sFlex.length - (sSubs.length+n);
            return String.fromCharCode(n+48) + sPfx + "/" + String.fromCharCode(m+48) + sSfx;
        }
        return sStem;
    },

    changeWordWithAffixCode: function (sWord, sAffCode) {
        if (sAffCode == "0") {
            return sWord;
        }
        if (!sAffCode.includes("/")) {
            return sAffCode;
        }
        let [sPfxCode, sSfxCode] = sAffCode.split('/');
        sWord = sPfxCode.slice(1) + sWord.slice(sPfxCode.charCodeAt(0)-48);
        return sSfxCode[0] == '0' ? sWord + sSfxCode.slice(1) : sWord.slice(0, -(sSfxCode.charCodeAt(0)-48)) + sSfxCode.slice(1);
    }
};


if (typeof(exports) !== 'undefined') {
    exports.getStemFromSuffixCode = str_transform.getStemFromSuffixCode;
    exports.getStemFromAffixCode = str_transform.getStemFromAffixCode;
}